Question: You perform comparative genome hybridization by labeling wildtypc DNA red and homozygous_mutant 4…
Show transcribed image text You perform comparative genome hybridization by labeling wildtypc DNA red and homozygous_mutant 4 DNA green, and probing normal chromosomes Below are the results: Describe mutation 4 based on the results above. Mutant 4 has a duplication of region 2-3 After DNA sequencing you find that mutant 4 and mutant 5 affect the same gene. Mutant 5 has a pericentric inversion with one breakpoint at region 2 on chromosome 2. If you performed comparative genomic hybridization by labeling homozygous mutant 5 DNA red and homozygous mutant 4 DNA green, and probing normal chromosomes, what you expect to see? (Circle your answer). The same result as shown above The ratio of red green would be 2.0 for region 2 The ratio of red: green would be 0.67 for region 2 The ratio of red green would be 1.0 for region 2 None of the above
You perform comparative genome hybridization by labeling wildtypc DNA red and homozygous_mutant 4 DNA green, and probing normal chromosomes Below are the results: Describe mutation 4 based on the results above. Mutant 4 has a duplication of region 2-3 After DNA sequencing you find that mutant 4 and mutant 5 affect the same gene. Mutant 5 has a pericentric inversion with one breakpoint at region 2 on chromosome 2. If you performed comparative genomic hybridization by labeling homozygous mutant 5 DNA red and homozygous mutant 4 DNA green, and probing normal chromosomes, what you expect to see? (Circle your answer). The same result as shown above The ratio of red green would be 2.0 for region 2 The ratio of red: green would be 0.67 for region 2 The ratio of red green would be 1.0 for region 2 None of the above
