Question: #1 Oligomycin, an antibiotic, acts by binding ATP synthase and blocking the proton channel. What …

#1 Oligomycin, an antibiotic, acts by binding ATP
synthase and blocking the proton channel. What would be expected to
happen to the H⁺ gradient with the introduction of
oligomyciin?

Select one:

A. H⁺ would stop being pumped from the matrix into
the intermembrane space.

B. The buildup of H⁺ in the intermembrane space would
eventually overcome oligomycin and ATP would continue to be
generated.

C. The H⁺ gradient would be unaffected.

D. H⁺ would begin to flow from the intermembrane
space into the matrix back through the proton pump complexes of the
ETC.

#2 One of the effects of insulin is an increase the
number of glucose transporters in the plasma membrane. Consider
this table indicating four glucose transporters (GLUT) and their
K_M values. Typical blood glucose concentration is 4-8
mM. Which of the GLUT transporters would be least able to provide
increased flux of glucose into a muscle cell?

transporter	KM (mM)
GLUT1	1
GLUT2	15-20
GLUT3	1
GLUT4	5

Select one:

A. GLUT1

B. GLUT2

C. GLUT3

D. GLUT4

#3 Mitochondria with
proton-permeable inner membranes would exhibit which of the
following properties?

Select one:

A. Inability to perform the citric acid cycle.

B. Inhibition of the pyruvate dehydrogenase complex.

C. Inability to engage the electron transport chain.

D. Insufficient ATP production.

#4 Muscle fibers come in
two types: fast twitch and slow twitch. Fast twitch fibers contract
quickly and fatigue quickly – they rely mainly on glycolysis for
energy production. Slow twitch muscle relies upon aerobic activity
for energy. Which of the following molecules would
not be expected to be produced in
fast
twitch muscle
metabolism.

Select one:

A. CO₂

B. ADP

C. 1,3-bisphosphoglycerate

D. pyruvate

#5 Consider the
regulation of glucose. Why is hexokinase not the committed step in
glycolysis?

Select one:

A. Because hexokinase is irreversible.

B. Because the product, glucose-6-phosphate, is used in other
pathways besides glycolysis.

C. Because its product, glucose-6-phosphate, regulates
hexokinase activity through negative feedback.

D. Because hexokinase is exergonic.

E. Because the reaction is reversible.