Question: 1)The p-value corresponding to the chi-square test of independence on alleles is 0.004. If there …

3)Applying the chi-square test of independence to case and control
genotypes at five SNPs (labeled SNP01, SNP02, SNP03, SNP04, SNP05),
yields the respective p-values 0.05, 0.04, 0.009, 0.004, and 0.10.
The genetic phenotype is Fructosia.

After Bonferroni correction for multiple testing, what SNPs are
declared to be significantly associated with Fructosia at the 5%
significance level?

4)In what 10-year period did researchers develop technologies for
genotyping Single Nucleotide Polymorphisms?

5)What is the Chi-square test on independence for genotypes value
for the following contingency table?